Profile Analysis for One Sample with Hotelling's T-Square

The paos function implements profile analysis for one sample using Hotelling's T-square.

paos(data, scale = TRUE)

Arguments

data

A data matrix or data frame; rows represent individuals, columns represent variables.

scale

If TRUE (default), variables are standardized by dividing their standard deviations.

Value

A summary table is returned, listing the following two hypothesis:

  • Hypothesis 1 - Ratios of the means of the variables over the hypothesized mean are equal to 1.

  • Hypothesis 2 - All of the ratios are equal to each other.

Details

The paos function runs profile analysis for one sample based on the Hotelling's T-square test and tests the two htypothesis. First, the null hypothesis that all the ratios of the variables in the data are equal to 1. After rejecting the first hypothesis, a secondary null hypothesis that all of the ratios of the variables in the data equal to one another (not necessarily equal to 1) is tested.

See also

cpa, pr

Examples

if (FALSE) {
data(nutrient) 
paos(nutrient, scale=TRUE)
}